Revision 17 as of 2009-10-03 02:04:31

Clear message

I'm looking for information on Python bit manipulation, binary manipulation.

It seems that there are no modules for performing Python bit manipulation.

I personally want to be able to:

The closest thing I've found is ASPN: bit-field manipulation.

I imagine that there are many more manipulations people would like to do with bits.

Manipulations

To integer.

   1 >>> print int('00100001', 2)
   2 33

To hex string. Note that you don't need to use x8 bits.

   1 >>> print "0x%x" % int('11111111', 2)
   2 0xff
   3 >>> print "0x%x" % int('0110110110', 2)
   4 0x1b6
   5 >>> print "0x%x" % int('0010101110101100111010101101010111110101010101', 2)
   6 0xaeb3ab57d55

To character. 8 bits max.

   1 >>> chr(int('111011', 2))
   2 ';'
   3 >>> chr(int('1110110', 2))
   4 'v'
   5 >>> chr(int('11101101', 2))
   6 '\xed'

Characters to integers, but not to strings of 1's and 0's.

   1 >>> int('01110101', 2)
   2 117
   3 >>> chr(int('01110101', 2))
   4 'u'
   5 >>> ord('u')
   6 117

Individual bits.

   1 >>> 1 << 0
   2 1
   3 >>> 1 << 1
   4 2
   5 >>> 1 << 2
   6 4
   7 >>> 1 << 3
   8 8
   9 >>> 1 << 4
  10 16
  11 >>> 1 << 5
  12 32
  13 >>> 1 << 6
  14 64
  15 >>> 1 << 7
  16 128

Transformations Summary

Strings to Integers:

Integers to Strings:

We are still left without a technique for producing binary strings, and decyphering hex strings.

Hex String to Integer

The simplest approach is to use the int type with the base argument.

   1 >>> int('0xff',16)
   2 255
   3 >>> int('d484fa894e',16)
   4 912764078414

Another approach to decyphering "0xdecafbad" style hex strings, is to use eval:

   1 >>> eval("0xdecafbad ")
   2 3737844653L

However, this could be dangerous, depending on where you're getting your data from.

Here's a function that is safer:

   1 def hex_to_integer(h):
   2     """Convert a hex string to an integer.
   3 
   4     The hex string can be any length. It can start with an 0x, or not.
   5     Unrecognized characters will raise a ValueError.
   6 
   7     This function released into the public domain by it's author, Lion
   8     Kimbro.
   9     """
  10     num = 0  # Resulting integer
  11     h = h.lower()  # Hex string
  12     if h[:2] == "0x":
  13         h = h[2:]
  14     for c in h:  # Hex character
  15         num = num * 16
  16         if "0" <= c <= "9":
  17             num = num + (ord(c) - ord("0"))
  18         elif "a" <= c <= "f":
  19             num = num + (ord(c) - ord("a"))
  20             num = num + 10
  21         else:
  22             raise ValueError(c)
  23     return num

Integer to Bin String

Python 3 supports binary literals (e.g. 0b10011000) and has a bin() function. For older versions:

   1 >>> def bin(a):
   2         s=''
   3         t={'0':'000','1':'001','2':'010','3':'011',
   4            '4':'100','5':'101','6':'110','7':'111'}
   5         for c in oct(a)[1:]:
   6                 s+=t[c]
   7         return s

Python Integers

From "The Python Language Reference" page on the Data Model:

"Integers (int) These represent numbers in an unlimited range, subject to available (virtual) memory only. For the purpose of shift and mask operations, a binary representation is assumed, and negative numbers are represented in a variant of 2’s complement which gives the illusion of an infinite string of sign bits extending to the left."

Unless you know you are working with numbers that are less than a certain length, for instance numbers from arrays of integers, shifts, rotations, etc. may give unexpected results. There does not seem to be a way to determine how Python represents a specific integer internally, i.e. how many bytes are used.

The number of the highest bit set is the highest power of 2 less than or equal to the input integer. This is the same as the exponent of the floating point representation of the integer, and is also called its "integer log base 2".(ref.1)

The easiest way to determine the highest bit set is:

   1 import math
   2 
   3 hiBit = math.floor(math.log(int_type, 2))

An input less than or equal to 0 results in a "ValueError: math domain error"

The section "Finding integer log base 2 of an integer" on the "Bit Twiddling Hacks"(ref.1) web page includes a number of methods for determining this value for integers of known magnitude, presumably when no math coprocessor is available. The only method generally applicable to Python integers of unknown magnitude is the "obvious way" of counting the number of bitwise shift operations needed to reduce the input to 0.

Bit Length Of a Python Integer

bitLen() counts the actual bit length of a Python integer, that is, the number of the highest non-zero bit plus 1. Zero, with no non-zero bit, returns 0. As should be expected from the quote above about "the illusion of an infinite string of sign bits extending to the left," a negative number throws the computer into an infinite loop.

The function can return any result up to the length of the largest integer your computer's memory can hold.

   1 def bitLen(int_type):
   2     length = 0
   3     while (int_type):
   4         int_type >>= 1
   5         length += 1
   6     return(length)
   7 
   8 for i in range(17):
   9      print(bitLen(i))
  10 
  11 # results: 0, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 5

The method using the math module is much faster, especially on huge numbers with hundreds of decimal digits.

bitLenCount()

In common usage, the "bit count" of an integer is the number of set (1) bits, not the bit length of the integer described above. bitLen() can be modified to also provide the count of the number of set bits in the integer. There are faster methods to get the count below.

   1 def bitLenCount(int_type):
   2     length = 0
   3     count = 0
   4     while (int_type):
   5         count += (int_type & 1)
   6         length += 1
   7         int_type >>= 1
   8     return(length, count)

Operations on Integers of Unknown Magnitude

Some proceedures don't need to know the magnitude of an integer to give meaningful results.

bitCount()

The proceedure and the information below were found in "Bit Twiddling Hacks"(ref.1)

Counting bits set, Brian Kernighan's way*

unsigned int v;          // count the number of bits set in v
unsigned int c;          // c accumulates the total bits set in v
for (c = 0; v; c++)
{   v &= v - 1;  }       //clear the least significant bit set

This method goes through as many iterations as there are set bits. So if we have a 32-bit word with only the high bit set, then it will only go once through the loop.

* The C Programming Language 2nd Ed., Kernighan & Ritchie, 1988.

Don Knuth pointed out that this method was published by Peter Wegner in CACM 3 (1960), 322. Also discovered independently by Derrick Lehmer and published in 1964 in a book edited by Beckenbach.

Kernighan and Knuth, potent endorsements!

This works because each subtraction "borrows" from the lowest 1-bit. For example:

   1 #       loop pass 1                 loop pass 2
   2 #      101000     101000           100000     100000
   3 #    -      1   & 100111         -      1   & 011111
   4 #    = 100111   = 100000         = 011111   =      0

It is an excellent technique for Python, since the size of the integer need not be determined beforehand.

   1 def bitCount(int_type):
   2     count = 0
   3     while(int_type):
   4         int_type &= int_type - 1
   5         count += 1
   6     return(count)

parityOf()

From "Bit Twiddling Hacks"

Code almost identical to bitCount(), above, calculates the parity of an integer, returning 0 if there are an even number of set bits, and -1 if there are an odd number. In fact, counting the bits and checking whether the result is odd with bitcount & 1 is about the same speed as the parity function.

   1 def parityOf(int_type):
   2     parity = 0
   3     while (int_type):
   4         parity = ~parity
   5         int_type = int_type & (int_type - 1)
   6     return(parity)

lowestSet()

To determine the bit number of the lowest bit set in an integer, in twos-complement notation i & -i zeroes all but the lowest set bit. The bitLen() proceedure then determines its position. Obviously, negative numbers return the same result as their opposite. In this version, an input of 0 returns -1, in effect an error condition.

   1 For example:
   2 #    00111000     # 56
   3 #    11001000     # twos complement, -56
   4 # &= 00001000

   1 def lowestSet(int_type):
   2     low = (int_type & -int_type)
   3     lowBit = -1
   4     while (low):
   5         low >>= 1
   6         lowBit += 1
   7     return(lowBit)

Single bits

The usual single-bit operations will work on any Python integer. It is up to the programmer to be sure that the value of 'offset' makes sense in the context of the program.

   1 # testBit() returns a nonzero result, 2**offset, if the bit at 'offset' is one.
   2 
   3 def testBit(int_type, offset):
   4     mask = 1 << offset
   5     return(int_type & mask)
   6 
   7 # setBit() returns an integer with the bit at 'offset' set to 1.
   8 
   9 def setBit(int_type, offset):
  10     mask = 1 << offset
  11     return(int_type | mask)
  12 
  13 # clearBit() returns an integer with the bit at 'offset' cleared.
  14 
  15 def clearBit(int_type, offset):
  16     mask = ~(1 << offset)
  17     return(int_type & mask)
  18 
  19 # toggleBit() returns an integer with the bit at 'offset' inverted, 0 -> 1 and 1 -> 0.
  20 
  21 def toggleBit(int_type, offset):
  22     mask = 1 << offset
  23     return(int_type ^ mask)

References

ref.1. "Bit Twiddling Hacks" By Sean Eron Anderson

ref.2. "The Art of Assembly Language" by Randall Hyde

ref.3. Hacker's Delight

this is the sort of thing we're looking for:

related modules:

see also: BitwiseOperators

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