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| [[en]] {{{#!rst byteplay Module Documentation ============================= About byteplay -------------- byteplay is a module which lets you easily play with Python bytecode. I wrote it because I needed to manipulate Python bytecode, but didn't find any suitable tool. Michael Hudson's bytecodehacks (http://bytecodehacks.sourceforge.net/) could have worked fine for me, but it only works with Python 1.5.2. I also looked at Phillip J. Eby's peak.util.assembler (http://cheeseshop.python.org/pypi/BytecodeAssembler), but it's intended at creating new code objects from scratch, not for manipulating existing code objects. So I wrote byteplay. The basic idea is simple: define a new type, named Code, which is equivalent to Python code objects, but, unlike Python code objects, is easy to play with. "Equivalent" means that every Python code object can be converted to a Code object and vice-versa, without losing any important information on the way. "Easy to play with" means... well, exactly that. The representation should be as simple as possible, letting the infrastructure sort out technical details which do not affect the final behaviour. If you are interested in changing the behaviour of functions, or in assembling functions on your own, you may find byteplay useful. You may also find it useful if you are interested in how Python's bytecode actually works - byteplay lets you easily play with existing bytecode and see what happens, which is a great way to learn. You are also welcome to check byteplay's (pure Python) code, to see how it manipulates real bytecode. byteplay can be downloaded from http://byteplay.googlecode.com/svn/trunk/byteplay.py . See http://code.google.com/p/byteplay/ for a bit more administrative info. Feel free to improve this document - that's why it's on the wiki! Also, if you find it useful, please drop me an email at noamraph at gmail dot com - it would be nice knowing that what I did was useful to someone... A Quick Example --------------- Let's start from a quick example, to give you a taste of what byteplay does. Let's define this stupid function:: >>> def f(a, b): ... print (a, b) ... >>> f(3, 5) (3, 5) Now, let's use byteplay to see what its bytecode is actually doing:: >>> from byteplay import * >>> from pprint import pprint >>> c = Code.from_code(f.func_code) >>> pprint(c.code) [(SetLineno, 2), (LOAD_FAST, 'a'), (LOAD_FAST, 'b'), (BUILD_TUPLE, 2), (PRINT_ITEM, None), (PRINT_NEWLINE, None), (LOAD_CONST, None), (RETURN_VALUE, None)] I hope that this is pretty clear if you are a bit familiar with bytecode. The Code object contains a list of all operations, which are pairs of (opcode, arg). Not all opcodes have an argument, so they have None as their argument. You can see that no external tables are used: in the raw bytecode, the argument of many opcodes is an index to a table - for example, the argument of the LOAD_CONST opcode is an index to the co_consts table, which contains the actual constants. Here, the argument is the constant itself. Also note the SetLineno "opcode". It is not a real opcode, but it is used to declare where a line in the original source code begins. Besides another special opcode defined by byteplay, which we will see later, all other opcodes are the real opcodes used by the Python interpreter. Ok, now let's play! Say we want to change the function, to print its arguments in reverse order. To do this, we will add a ROT_TWO opcode after the two arguments were loaded to the stack. See how simple it is:: >>> c.code[3:3] = [(ROT_TWO, None)] >>> f.func_code = c.to_code() >>> f(3, 5) (5, 3) Opcodes ------- We have seen that the code list contains opcode constants such as LOAD_FAST. These are instances of the Opcode class. The Opcode class is a subclass of int, which overrides the ``__repr__`` method to return the string representation of an opcode. This means that instead of using a constant such as LOAD_FAST, a numerical constant such as 124 can be used. Opcode instances are, of course, much easier to understand. The byteplay module creates Opcode instances for all the interpreter opcodes. They can be found in the ``opcodes`` set, and also in the module's global namespace, so you can write ``from byteplay import *`` and use the opcode constants immediately. byteplay doesn't include a constant for the EXTENDED_ARG opcode, as it is not used by byteplay's representation. Module Contents --------------- These are byteplay's public attributes, which are imported when ``from byteplay import *`` is done. ``opcodes`` A set of all Opcode instances. ``opmap`` A mapping from an opcode name to an Opcode instance. ``opname`` A mapping from an opcode number (and an Opcode instance) to its name. ``cmp_op`` A list of strings which represent comparison operators. In raw bytecode, the argument of the COMPARE_OP opcode is an index to this list. In the code list, it is the string representing the comparison. The following are sets of opcodes, which list opcodes according to their behaviour. ``hasarg`` This set contains all opcodes which have an argument (these are the opcodes which are >= HAVE_ARGUMENT). ``hasname`` This set contains all opcodes whose argument is an index to the co_names list. ``hasjrel`` This set contains all opcodes whose argument is a relative jump, that is, an offset by which to advance the byte code instruction pointer. ``hasjabs`` This set contains all opcodes whose argument is an absolute jump, that is, an address to which the instruction pointer should jump. ``hasjump`` This set contains all opcodes whose argument is a jump. It is simply ``hasjrel + hasjabs``. In byteplay, relative and absolute jumps behave in the same way, so this set is convinient. ``haslocal`` This set contains all opcodes which operate on local variables. ``hascompare`` This set contains all opcodes whose argument is a comparison operator - that is, only the COMPARE_OP opcode. ``hasfree`` This set contains all opcodes which operate on the cell and free variable storage. These are variables which are also used by an enclosing or an enclosed function. ``hascode`` This set contains all opcodes which expect a code object to be at the top of the stack. In the bytecode the Python compiler generates, they are always preceded by a LOAD_CONST opcode, which loads the code object. ``hasflow`` This set contains all opcodes which have a special flow behaviour. All other opcodes always continue to the next opcode after finished, unless an exception was raised. The following are used in the opcode list. ``Opcode`` The type of all opcode constants. ``SetLineno`` This singleton is used like the "real" opcode constants, but only declares where starts the bytecode for a specific line in the source code. ``Label`` This is the type of label objects. This class does nothing - it is used as a way to refer to a place in the code list. Here come some additional functions. ``isopcode(obj)`` Use this function to check whether the first element of an operation pair is a real opcode. This simply returns ``obj is not SetLineno and not isinstance(obj, Label)``. ``getse(op[, arg])`` This function gets the stack effect of an opcode, as a (pop, push) tuple. The stack effect is the number of items popped from the stack, and the number of items pushed instead of them. If an item is only inspected, it is considered as though it was popped and pushed again. This function is meaningful only for opcodes not in hasflow - for other opcodes, ValueError will be raised. For some opcodes the argument is needed in order to calculate the stack effect. In that case, if arg isn't given, ValueError will be raised. ``printcodelist(code, to=sys.stdout)`` This function gets a code list and prints it in a way easier to read. For example, let's define a simple function:: >>> def f(a): ... if a < 3: ... b = a ... >>> c = Code.from_code(f.func_code) This is the code list itself:: >>> pprint(c.code) [(SetLineno, 2), (LOAD_FAST, 'a'), (LOAD_CONST, 3), (COMPARE_OP, '<'), (JUMP_IF_FALSE, <byteplay.Label object at 0xb7c6a16c>), (POP_TOP, None), (SetLineno, 3), (LOAD_FAST, 'a'), (STORE_FAST, 'b'), (JUMP_FORWARD, <byteplay.Label object at 0xb7c6a18c>), (<byteplay.Label object at 0xb7c6a16c>, None), (POP_TOP, None), (<byteplay.Label object at 0xb7c6a18c>, None), (LOAD_CONST, None), (RETURN_VALUE, None)] And this is the nicer representation:: >>> printcodelist(c.code) 2 1 LOAD_FAST a 2 LOAD_CONST 3 3 COMPARE_OP < 4 JUMP_IF_FALSE to 11 5 POP_TOP 3 7 LOAD_FAST a 8 STORE_FAST b 9 JUMP_FORWARD to 13 >> 11 POP_TOP >> 13 LOAD_CONST None 14 RETURN_VALUE For your convinience, another class was defined: ``CodeList`` This class is a list subclass, which only overrides the __str__ method to use ``printcodelist``. If the code list is an instance of CodeList, you don't have to type ``printcodelist(c.code)`` in order to see the nice representation - just type ``print c.code``. Code instances created from raw Python code objects already have that feature! And, last but not least - the Code class itself! The Code Class -------------- Constructor ~~~~~~~~~~~ :: Code(code, freevars, args, varargs, varkwargs, newlocals, name, filename, firstlineno, docstring) -> new Code object This constructs a new Code object. The argument are simply values for the Code object data attributes - see below. Data Attributes ~~~~~~~~~~~~~~~ We'll start with the data attributes - those are read/write, and distinguish one code instance from another. First come the attributes which affect the operation of the interpreter when it executes the code, and then come attributes which give extra information, useful for debugging and introspection. ``code`` This is the main part which describes what a Code object does. It is a list of pairs ``(opcode, arg)``. ``arg`` is the opcode argument, if it has one, or None if it doesn't. ``opcode`` can be of 3 types: * Regular opcodes. These are the opcodes which really define an operation of the interpreter. They can be regular ints, or Opcode instances. The meaning of the argument changes according to the opcode: - Opcodes not in ``hasarg`` don't have an argument. None should be used as the second item of the tuple. - The argument of opcodes in ``hasconst`` is the actual constant. - The argument of opcodes in ``hasname`` is the name, as a string. - The argument of opcodes in ``hasjump`` is a Label instance, which should point to a specific location in the code list. - The argument of opcodes in ``haslocal`` is the local variable name, as a string. - The argument of opcodes in ``hascompare`` is the string representing the comparison operator. - The argument of opcodes in ``hasfree`` is the name of the cell or free variable, as a string. - The argument of the remaining opcodes is the numerical argument found in raw bytecode. Its meaning is opcode specific. * ``SetLineno``. This is a singleton, which means that a line in the source code begins. Its argument is the line number. * labels. These are instances of the ``Label`` class. The label class does nothing - it is just used as a way to specify a place in the code list. Labels can be put in the code list and cause no action by themselves. They are used as the argument of opcodes which may cause a jump to a specific location in the code. ``freevars`` This is a list of strings - the names of variables defined in outer functions and used in this function or in functions defined inside it. The order of this list is important, since those variables are passed to the function as a sequence whose order should match the order of the ``freevars`` attribute. A few words about closures in Python may be in place. In Python, functions defined inside other functions can use variables defined in an outer function. We know each running function has a place to store local variables. But how can functions refer to variables defined in an outer scope? The solution is this: for every variable which is used in more than one scope, a new ``cell`` object is created. This object does one simple thing: it refers to one another object - the value of its variable. When the variable gets a new value, the cell object is updated too. A reference to the cell object is passed to any function which uses that variable. When an inner function is interested in the value of a variable of an outer scope, it uses the value referred by the cell object passed to it. An example might help understand this. Let's take a look at the bytecode of a simple example:: >>> def f(): ... a = 3 ... b = 5 ... def g(): ... return a + b ... >>> from byteplay import * >>> print c.code 2 1 LOAD_CONST 3 2 STORE_DEREF a 3 4 LOAD_CONST 5 5 STORE_DEREF b 4 7 LOAD_CLOSURE a 8 LOAD_CLOSURE b 9 BUILD_TUPLE 2 10 LOAD_CONST <byteplay.Code object at 0xb7c6a56c> 11 MAKE_CLOSURE 0 12 STORE_FAST g 13 LOAD_CONST None 14 RETURN_VALUE >>> c.code[10][1].freevars ('a', 'b') >>> print c.code[10][1].code 5 1 LOAD_DEREF a 2 LOAD_DEREF b 3 BINARY_ADD 4 RETURN_VALUE We can see that LOAD_DEREF and STORE_DEREF opcodes are used to get and set the value of cell objects. There is no inherent difference between cell objects created by an outer function and cell objects used in an inner function. What makes the difference is whether a variable name was listed in the ``freevars`` attribute of the Code object - if it was not listed there, a new cell is created, and if it was listed there, the cell created by an outer function is used. We can also see how a function gets the cell objects it needs from its outer functions. The inner function is created with the MAKE_CLOSURE opcode, which pops two objects from the stack: first, the code object used to create the function. Second, a tuple with the cell objects used by the code (the tuple is created by the LOAD_CLOSURE opcodes, which push a cell object into the stack, and of course the BUILD_TUPLE opcode.) We can see that the order of the cells in the tuple match the order of the names in the ``freevars`` list - that's how the inner function knows that ``(LOAD_DEREF, 'a')`` means "load the value of the first cell in the tuple". ``args`` The list of arguments names of a function. For example:: >>> def f(a, b, *args, **kwargs): ... pass ... >>> Code.from_code(f.func_code).args ('a', 'b', 'args', 'kwargs') ``varargs`` A boolean: Does the function get a variable number of positional arguments? In other words: does it have a ``*args`` argument? If ``varargs`` is True, the argument which gets that extra positional arguments will be the last argument or the one before the last, depending on whether ``varkwargs`` is True. ``varkwargs`` A boolean: Does the function get a variable number of keyword arguments? In other words: does it have a ``**kwargs`` argument? If ``varkwargs`` is True, the argument which gets the extra keyword arguments will be the last argument. ``newlocals`` A boolean: Should a new local namespace be created for this code? This is True for functions and False for modules and exec code. Now come attributes with additional information about the code: ``name`` A string: The name of the code, which is usually the name of the function created from it. ``filename`` A string: The name of the source file from which the bytecode was compiled. ``firstlineno`` An int: The number of the first line in the source file from which the bytecode was compiled. ``docstring`` A string: The docstring for functions created from this code. Methods ~~~~~~~ These are the Code class methods. ``Code.from_code(code) -> new Code object`` This is a static method, which creates a new Code object from a raw Python code object. It is equivalent to the raw code object, that is, the resulting Code object can be converted to a new raw Python code object, which will have exactly the same behaviour as the original object. ``code.to_code() -> new code object`` This method converts a Code object into an equivalent raw Python code object, which can be executed just like any other code object. ``code1.__eq__(code2) -> bool`` Different Code objects can be meaningfully tested for equality. This tests that all attributes have the same value. For the code attribute, labels are compared to see if they form the same flow graph. Stack-depth Calculation ----------------------- What was described above is enough for using byteplay. However, if you encounter an "Inconsistent code" exception when you try to assemble your code and wonder what it means, or if you just want to learn more about Python's stack behaviour, this section is for you. Note: This section isn't as clear as it could have been, to say the least. If you like to improve it, feel free to do so - that's what wikis are for, aren't they? When assembling code objects, the code's maximum stack usage is needed. This is simply the maximum number of items expected on the frame's stack. If the actual number of items in stack exceeds this, Python may well fail with a segmentation fault. The question is then, how to calculate the maximum stack usage of a given code? There's most likely no general solution for this problem. However, code generated by Python's compiler has a nice property which makes it relatively easy to calculate the maximum stack usage. The property is that if we take a bytecode "line", and check the stack state whenever we reach that line, we will find the stack state when we reach that line is always the same, no matter how we got to that line. We'll call such code "regular". Now, this requires clarification: what is the "stack state" which is always the same, exactly? Obviously, the stack doesn't always contain the same objects when we reach a line. For now, we can assume that it simply means the number of items on the stack. This helps us a lot. If we know that every line can have exactly one stack state, and we know how every opcode changes the stack state, we can trace stack states along all possible code paths, and find the stack state of every reachable line. Then we can simply check what state had the largest number of stack items, and that's the maximum stack usage of the code. What will happen with code not generated by Python's compiler, if it doesn't fulfill the requirement that every line should have one state? When tracing the stack state for every line, we will find a line, which can be reached from several places, whose stack state changes according to the address from which we jumped to that line. In that case, An "Inconsistent code" exception will be raised. Ok, what is really what we called "stack state"? If every opcode pushed and popped a constant number of elements, the stack state could have been the number of items on stack. However, life isn't that simple. In real life, there are *blocks*. Blocks allow us to break from a loop, regardless of exactly how many items we have in stack. How? Simple. Before the loop starts, the SETUP_LOOP opcode is executed. This opcode records the number of opcodes currently in stack, and also a position in the code. This information is discarded when the POP_BLOCK opcode is executed. But if the BREAK_LOOP opcode is executed instead of POP_BLOCK, two things happen. One is that the execution jumps to the position specified by the SETUP_LOOP opcode. The other is that all elements pushed into the stack since the PUSH_BLOCK op are popped. Fortunately, we can still live with that. Instead of defining the stack state as a single number - the total number of elements in the stack, we will define the stack state as a sequence of numbers - the number of elements in the stack per each block. So, for example, if the state was (3, 5), after a BINARY_ADD operation the state will be (3, 4), because the operation pops two elements and pushes one element. If the state was (3, 5), after a PUSH_BLOCK operation the state will be (3, 5, 0), because a new block, without elements yet, was pushed. Another complication: the SETUP_FINALLY opcode specifies an address to jump to if an exception is raised or a BREAK_LOOP operation was executed. This address can also be reached by normal flow. However, the stack state in that address will be different, depending on what actually happened - if an exception was raised, 3 elements will be pushed, if BREAK_LOOP was executed, 2 elements will be pushed, and if nothing happened, 1 element will be pushed by a LOAD_CONST operation. This seemingly non-consistent state always ends with an END_FINALLY opcode. The END_FINALLY opcodes pops 1, 2 or 3 elements according to what it finds on stack, so we return to "consistent" state. How can we deal with that complexity? The solution is pretty simple. We will treat the region between the SETUP_FINALLY target and the END_FINALLY opcode as though 3 elements are always pushed into it, and treat the END_FINALLY opcode as though it always pops 3 elements. That's all! Just be aware of that when you are playing with SETUP_FINALLY and END_FINALLY opcodes... }}} |
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